# Question cf103

May 14, 2015

The molarity of your diluted solution will be 0.175 M.

When you dilute a solution, what you're essentially doing is keeping the number of moles of solute constant, and increasing the volume of the solution.

Since molarity is defined as moles of solute per liter of solution, increasing the volume of the solution while keeping the number of moles of solute constant will result in a decreased concentration.

$C = \frac{n}{V} = \text{constant"/V => C * V = "constant}$

This means that you have

${C}_{1} {V}_{1} = {C}_{2} {V}_{2}$, where

${C}_{1}$, ${V}_{1}$ - the concentration and volume of the initial solution;
${C}_{2}$,${V}_{2}$ - the concentration and volume of the diluted solution.

$\text{1.75 M" * "10.0 mL" = C_2 * "100.0 mL}$
C_2 = (10.0cancel("mL"))/(100.0cancel("mL")) * "1.75 M" = color(green)("0.175 M")#