Question #1560d

1 Answer
Jun 2, 2015

Nucleophilic substitution by "KCN" gives an alkyl cyanide, while "AgCN" gives an alkyl isocyanide because "KCN" is ionic and "AgCN" is covalent.

Explanation:

Alkyl halides react with alcoholic "KCN" to form alkyl cyanides

"KCN" is an ionic compound. The nucleophile is the cyanide ion

[:stackrel("-1") ("C")"≡N:"]^"-"

The carbon atom is the nucleophile and the reaction is

underbrace("RX")_color(red)("alkyl halide") + :stackrel("-")("C")"≡N:" stackrel("Δ"color(white)(m)) (→)underbrace("RCN")_color(red)("alkyl cyanide") + "X"^"-"

Alkyl halides react with alcoholic silver cyanide to form alkyl isocyanides.

The electronegativity difference between "Ag" and "C" is so small that the "Ag-C" bond is over 90 % covalent.

The nucleophile is "Ag-C≡N:".

The carbon atom is no longer available to act as a nucleophile, but the N atom can still attack the alkyl halide.

underbrace("RX")_color(red)("alkyl halide") + "AgCN:" stackrel("Δ"color(white)(m)) (→)underbrace("RNC")_color(red)("alkyl isocyanide") + "AgX"