SN1 and SN2 Reactions

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Organic Chemistry | SN1 and SN2 Practice Questions - Chair Conformation.

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Key Questions

  • Answer:

    A two-step nucleophilic substitution reaction.


    In this mechanism, a leaving group leaves a molecule, resulting in a carbocation. In a separate step, a nucleophile coordinates to the carbocation, resulting in a substitution product.

  • Answer:

    See explanation.


    When something that has high electron dencity ( nucleophilic ) approches a #"sp"^3# carbon and it forms a bond with it while the same time that the new bond is made one of the old one is destroyed.

    As you can see here the #"Nu"# hits the #"C"# and the #"X"# that was previously bonded with the #"C"# is slowly leaving the bond the exact same time that the nu is forming it.

    In the transition state the exact amount / percentance of the bond that is formed the exact same has started to loosen. at the end nu takes the place of the x that is now freed of the atom

    You have to keep in mind that #"S"_"N"2# doesnt always happen because your #"X"# has to have very weak bonding with the #"C"# so that it can leave easily ( like #"Cl"^(-)# or #"Br"^(-)# ). You should also remember that the stereochemistry of the atom always changes

  • Nucleophilic substitution is the reaction of an electron pair donor (the nucleophile) with an electron pair acceptor (the electrophile).

    The most general form for the reaction may be given as

    Nuc: + R-LG → R-Nuc + LG:

    The electron pair (:) from the nucleophile(Nuc) attacks the substrate (R-LG) forming a new bond, while the leaving group (LG) departs with an electron pair.

    For example:


  • Rory K. answered · 11 months ago

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Nucleophilic Substitution Reactions (SN1 and SN2) and Elimination Reactions (E1 and E2)