Question #78cc1

1 Answer
Feb 19, 2017

Answer:

Here's how I do it.

Explanation:

cis-1,3-diethylcyclohexane

Start with a basic cyclohexane chair.

cyclohexane

Draw the axial and equatorial bonds at atoms 1 and 3.

1,3-Cyclohexane

Insert ethyl groups at the two equatorial positions

1,3-Diequatorial

And we have our structure.

(#1R,3S#) -1-chloro-3methylcyclohexane

Draw an arbitrary structure with both groups on wedges and assign configurations.

cis-1,3

#"C-1"# is (#R#) and #"C-3"# is (#S#). Hey, I got them both right!

If any had been wrong, I would have interchanged the wedge and dash on that carbon.

Now we must draw the conformation.

This is also a cis-1,3-disubstituted cyclohexane, so we put the substituents in the equatorial positions.

1-chloro-3-methyl

Again, we have our structure.