Question #78cc1

1 Answer
Feb 19, 2017

Here's how I do it.

Explanation:

cis-1,3-diethylcyclohexane

Start with a basic cyclohexane chair.

cyclohexanecyclohexane

Draw the axial and equatorial bonds at atoms 1 and 3.

1,3-Cyclohexane1,3-Cyclohexane

Insert ethyl groups at the two equatorial positions

1,3-Diequatorial1,3-Diequatorial

And we have our structure.

(1R,3S) -1-chloro-3methylcyclohexane

Draw an arbitrary structure with both groups on wedges and assign configurations.

cis-1,3cis-1,3

"C-1" is (R) and "C-3" is (S). Hey, I got them both right!

If any had been wrong, I would have interchanged the wedge and dash on that carbon.

Now we must draw the conformation.

This is also a cis-1,3-disubstituted cyclohexane, so we put the substituents in the equatorial positions.

1-chloro-3-methyl1-chloro-3-methyl

Again, we have our structure.