Question #78cc1

Feb 19, 2017

Here's how I do it.

Explanation:

cis-1,3-diethylcyclohexane

Draw the axial and equatorial bonds at atoms 1 and 3.

Insert ethyl groups at the two equatorial positions

And we have our structure.

($1 R , 3 S$) -1-chloro-3methylcyclohexane

Draw an arbitrary structure with both groups on wedges and assign configurations.

$\text{C-1}$ is ($R$) and $\text{C-3}$ is ($S$). Hey, I got them both right!

If any had been wrong, I would have interchanged the wedge and dash on that carbon.

Now we must draw the conformation.

This is also a cis-1,3-disubstituted cyclohexane, so we put the substituents in the equatorial positions.

Again, we have our structure.