Question #605aa

1 Answer
May 3, 2016

Answer:

#V_2=9.06mL#

Explanation:

Since the number of mole #n# is constant and the factors changing are the volume, the pressure and temperature; we can modify the ideal gas law #PV=nRT# to be:

#(PV)/T=k# where #k=nR# is constant.

Therefore, #(P_1V_1)/(T_1)=(P_2V_2)/(T_2)#

#=>V_2=(P_1V_1)/(T_1)xx(T_2)/(P_2)=(0.975cancel(atm)xx8.88mL)/(261cancel(K))xx(273cancel(K))/(1cancel(atm))=9.06mL#

Therefore, the volume of the gas at STP would be #V_2=9.06mL#.