Question #71dff

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Answer 1 · 2017-01-26T08:37:31

Ist part of the expression

#=3(sinx-cosx)^4#

#=3(sin^2x+cos^2x-2sinxcosx)^2#

#=3(1-2sinxcosx)^2#

#=3-12sinxcosx+12sin^2xcos^2x#

2nd part of the expression

#=6(sinx+cosx)^2#

#=6(sin^2x+cos^2x+2sinxcosx)#

#=6+12sinxcosx#

3rd part of the expression

#=4(sin^6x+cos^6x)#

#=4((sin^2x+cos^2x)^3-3sin^2xcos^2x(sin^2x+cos^2x)#

#=4(1-3sin^2xcos^2x)#

#=4-12sin^2xcos^2x#

So whole part

#= 3 -12sinxcosx+12sin^2xcos^2x +6+12sinxcosx+4-12sin^2xcos^2x#

#=13#