Question #1e11d

1 Answer
Aug 21, 2017

Here's how I see it.

Explanation:

We can think of the "HgI"_3^"-" as being formed by the reaction

"Hg"^"2+" + 3"I"^"-" → "HgI"_3^"-"

The electron configuration of a neutral "Hg" atom is

"Hg"^0 = "[Xe] 6s"^2 "4f"^14 "5d"^10

For "Hg"^"2+", the electron configuration is

"Hg"^"2+" = "[Xe] 4f"^14 "5d"^10

The "Hg"^"2+" ion, however, has vacant "6s" and "6p" orbitals.

It can hybridize a "6s" and two of the "6p" orbitals to form three new vacant "sp"^3 hybrid orbitals.

These can each overlap with a filled "5p" orbital of an iodide ion.

Thus, the new ion is trigonal planar, and the "Hg-I" bonds are coordinate covalent bonds in which the iodide ions are contributing both electrons of the covalent bond.