# Question #16d81

Nov 5, 2016

Hybridization of C in ${C}_{2} {H}_{4}$ is $s {p}^{2.}$

#### Explanation:

In ${C}_{2} {H}_{4}$, both the carbon atoms have got two sigma bonded connections with the two hydrogen atoms each. And the two carbon atoms got interconnected via one sigma bond and one pi bond.

$\therefore$ Hybridization $=$ Total no. of sigma bonded connections.
$\therefore$ Hybridization $=$ $2 + 1$ $=$ 3.

Now, 3 represents three hybridized orbitals, i.e. $s {p}^{2.}$