Question #af2a7

1 Answer
Oct 20, 2017

Answer:

Option (D) is correct

Explanation:

drawn

Let us consider a sector of #XOY# of a circle of radius #r# which has been formed by an arc of length #S#. This arc subtends angle #theta # radian at the center #O# of the circle.

Now #S/r=theta#

#=>S=rtheta....[1]#

Let the perimeter of the sector #P=S+2r......[2]#

Combining [1] and [2] we get

#P=rtheta +2#

#=>r=P/(theta+2).....[3]#

Now area of the sector #A=(pir^2)/(2pi)xxtheta#

#=>A=r^2/2xxtheta.....[4]#

Combining [3] and [4] we get

#A=1/2xxP^2/(theta+2)^2xxtheta#

Now

#A=P^2/2xxtheta/(theta^2+4theta+4)#

#=>A=P^2/2xx1/(theta+4+4/theta)#

#=>A=P^2/2xx1/((sqrttheta-2/sqrttheta)^2+8).....[5]#

By the given condition the perimeter #P# of the sector is fixed or constant . So #A# will be maximum when denominator of the RHS of [5] is minimum and this is possible only when

#(sqrttheta-2/sqrttheta)=0#

#=>theta =2# radian

Hence option (D) is correct