Question #e5006

1 Answer
Dec 25, 2017

Answer:

#=96.2gCaCO_3#

Explanation:

  1. Write the skeleton and balance the given equation
    #Ca(OH)_2(s)+CO_2(g)>CaCO_3(s)+H_2O(g)#
  2. Find the molar mass of #CaCO_3# as the involved compound as specified in the problem.
    #=(100g)/(mol)#
  3. Since the given data is already expressed in #mol#, conversion per convention is no longer necessary in this case.
  4. Referring to the balanced equation shown above for the mole ratio, find the #etaCaCO_3# through molar conversion; i.e.,
    #=0.962cancel(molCa(OH))_2xx(1molCaCO_3)/(1cancel(molCa(OH)_2))#
    #=0.962molCaCO_3#
  5. Now, find the #"mass"(m)# of #CaCO_3#, knowing the #etaCaCO_3# as computed, and the molar mass of the compound for the conversion.
    #=0.962cancel(molCaCO_3)xx(100gCaCO_3)/(1cancel(molCaCO_3))#
    #=96.2gCaCO_3#