Question #7738f

Jan 28, 2017

$\left(3 , 5\right)$

Explanation:

To graph these $\textcolor{b l u e}{\text{linear equations}}$ we can find the
$\textcolor{b l u e}{\text{x and y intercepts}} .$

When a line crosses the y-axis, the value of the corresponding x-coordinate is zero.
Substituting x = 0 into the equation gives us the value of the
$\textcolor{b l u e}{\text{y-intercept}}$

Similarly when the line crosses the x-axis, the y-coordinate is zero and substituting y = 0 into the equation gives the value of the $\textcolor{b l u e}{\text{x-intercept}}$

$\textcolor{b l u e}{\text{ equation :}} x - y = - 2$

$x = 0 \to 0 - y = - 2 \to y = 2 \leftarrow \textcolor{red}{\text{ y-intercept}}$

$y = 0 \to x - 0 = - 2 \to x = - 2 \leftarrow \textcolor{red}{\text{x-intercept}}$

Plot the points (0 ,2) and (-2 ,0) and draw a straight line through them.

$\textcolor{b l u e}{\text{equation :}} x + y = 8$

$x = 0 \to 0 + y = 8 \to y = 8 \leftarrow \textcolor{red}{\text{y-intercept}}$

$y = 0 \to x + 0 = 8 \to x = 8 \leftarrow \textcolor{red}{\text{x-intercept}}$

On the same grid as the previous points, plot (0 ,8) and (8 ,0)

The solution to the system is at $\textcolor{b l u e}{\text{ the point of intersection of the 2 lines}}$
graph{(y-x-2)(y+x-8)=0 [-10, 10, -5, 5]}