# Question #7738f

##### 1 Answer

#### Answer:

#### Explanation:

To graph these

#color(blue)"linear equations"# we can find the

#color(blue)"x and y intercepts".# When a line crosses the y-axis, the value of the corresponding x-coordinate is zero.

Substituting x = 0 into the equation gives us the value of the

#color(blue)"y-intercept"# Similarly when the line crosses the x-axis, the y-coordinate is zero and substituting y = 0 into the equation gives the value of the

#color(blue)"x-intercept"#

#color(blue)" equation :" x-y=-2#

#x=0to0-y=-2toy=2larrcolor(red)" y-intercept"#

#y=0tox-0=-2tox=-2larrcolor(red)"x-intercept"# Plot the points (0 ,2) and (-2 ,0) and draw a straight line through them.

#color(blue)"equation :"x+y=8#

#x=0to0+y=8toy=8larrcolor(red)"y-intercept"#

#y=0tox+0=8tox=8larrcolor(red)"x-intercept"# On the same grid as the previous points, plot (0 ,8) and (8 ,0)

The solution to the system is at

#color(blue)" the point of intersection of the 2 lines"#

graph{(y-x-2)(y+x-8)=0 [-10, 10, -5, 5]}