# What mass of sodium nitrate is required to give 128*g of oxygen gas upon thermolysis of the salt?

Feb 26, 2017

Approx. $700 \cdot g$..........

#### Explanation:

We need a stoichiometric equation:

$N a N {O}_{3} \left(s\right) + \Delta \rightarrow N a N {O}_{2} \left(s\right) + \frac{1}{2} {O}_{2} \left(g\right)$

We require a $128 \cdot g$ mass of dioxygen gas, i.e. $\frac{128 \cdot g}{32.00 \cdot g \cdot m o {l}^{-} 1} = 4 \cdot m o l$.

Given the equation, clearly we need AT LEAST $8 \cdot m o l$ of $\text{sodium nitrate}$, i.e. 8*molxx85.00*g*mol^-1=??g