Question

Question #eaebb

Answer 1

The elastic potential energy is `=4.26J`

Explanation:

The spring constant is `k=5.2Nm^-1`

The elongation is `x=3.66-2.38=1.28m`

The potential elastic potential energy is

`PE=1/2kx^2`

`=1/2*5.2*1.28^2`

`=4.26J`