# Question #5231b

Assuming you're referring to the decomposition reaction $2 {\text{NaHCO"_3rarr"Na"_2"CO"_3+"H"_2"O"+"CO}}_{2}$,
$3.0 {\text{mol NaHCO"_3 xx (1"mol CO"_2)/(2"mol NaHCO"_3)=1.5"mol CO}}_{2}$