# Question #caf58

Apr 16, 2017

In Carbon monoxide there is no hybridization.

#### Explanation:

Carbon number 6 has six total electrons this gives an electron configuration. of $1 {s}^{2} 2 {s}^{2} 2 {p}^{2}$

This leaves the valance configuration of ${2}^{2} 2 {p}^{2}$

The two s electrons are paired and are not used in bonding.

The two p electrons are in different p orbitals and able to be used for bonding. Therefore Carbon in it ground state configuration can form only two bonds.

Oxygen with a configuration of $1 {s}^{2} 2 {s}^{2} 2 {p}^{4}$ can also form only two bonds so the formation of CO requires no hybridization.

C=O