What mass of carbon dioxide results from complete combustion of a 9.75⋅L volume of benzene?

1 Answer
anor277
Apr 20, 2017

We need (i) a stoichiometric equation...........

........and we get approx. 29⋅kg of carbon dioxide.

Explanation:

We will be requiring (i) C6H6(l)+152O2(g)→6CO2(g)+3H2O(l)

(ii) the density of benzene, ρbenzene=0.88⋅g⋅mL−1,

And (iii), equivalent quantities of benzene........

Moles of benzene=9.75⋅L×0.88⋅g⋅mL−1⋅103⋅mL⋅L−178.11⋅g⋅mol−1

=109.9⋅mol.

Given the stoichiometry, the resultant mass of carbon dioxide is......6×109.9⋅mol×44.01⋅g⋅mol−1≅29⋅kg

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