What mass of carbon dioxide results from complete combustion of a #9.75*L# volume of benzene?

1 Answer
Apr 20, 2017

Answer:

We need (i) a stoichiometric equation...........

........and we get approx. #29*kg# of carbon dioxide.

Explanation:

We will be requiring #(i)# #C_6H_6(l) + 15/2O_2(g) rarr 6CO_2(g) + 3H_2O(l)#

#(ii)# the density of benzene, #rho_"benzene"=0.88*g*mL^-1#,

And #(iii)#, equivalent quantities of benzene........

#"Moles of benzene"=(9.75*Lxx0.88*g*mL^-1*10^3*mL*L^-1)/(78.11*g*mol^-1)#

#=109.9*mol#.

Given the stoichiometry, the resultant mass of carbon dioxide is......#6xx109.9*molxx44.01*g*mol^-1~=29*kg#