What occurs when a #190*mL# volume of barium nitrate at #0.105*mol*L^-1# concentration is mixed with #170*mL# volume of sodium sulfate at #0.100*mol*L^-1# concentration?

1 Answer
Apr 27, 2017

Answer:

#"Barium sulfate"# is a water insoluble salt.

Explanation:

The stoichiometric reaction is:

#Ba^(2+) + SO_4^(2-) rarr BaSO_4(s)darr#

And so we work out the molar equivalence of barium and sulfate ions.

#"Moles of sulfate ion"-=170xx10^-3Lxx0.100*mol*L^-1=0.0170*mol.#

#"Moles of barium ion"-=190xx10^-3Lxx0.105*mol*L^-1=0.01995*mol.#

And thus, clearly, sulfate dianion is the limiting reagent. And #0.0170*mol# #BaSO_4# should precipitate as a white solid. This represents a mass of................

#0.0170*cancel(mol)xx233.43*g*cancel(mol^-1)=3.96*g#.