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Question #4187f

1 Answer

May 3, 2017

120 mL

Explanation:

#n mol C_6H_6 = (39g)/(78g/(mol)# = #0.4997mol#

#(15mol O_2)/(2 mol C_6H_6) times 0.4997 mol C_6H_6# = #3.784mol O_2#

#Grams O_2 = mass O_2 = n times MW O_2 = 3.784 times 32 = 119.9g#
Density liquid #O_2 = 1.1 g/(mL), therefore,# amount in grams = 119.9

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