Question #9ca43

1 Answer
May 24, 2017

Answer:

#1.83 "mol Fe"_2"O"_3#

Explanation:

We can solve this problem by converting the given mass of #"Al"# to moles, and then use the stoichiometric relationships (the coefficients) in the chemical equation to convert to moles of #"Fe"_2"O"_3#:

#99.0cancel("g Al")((1 cancel("mol Al"))/(26.98 cancel("g Al")))((1 "mol Fe"_2"O"_3)/(2 cancel("mol Al"))) = color(red)(1.83 "mol Fe"_2"O"_3#