Question

For `Z=57`, what is the element, and what is its electronic configuration?

Answer 1

Got a Periodic Table............?

Explanation:

I actually happen to know this one, because I did a lot of work with lanthanides, and actinides. Anyway, `Z=57` SPECIFIES the element `"lanthanum"`. And thus the electronic configuration has an xenon core (`Xe, Z=54`), i.e. `[Xe]5d^(1)6s^(2)`. Lanthanum usually adopts the `+III` oxidation state, i.e. `{[Xe]}^(3+)`.....