Question #4e4a9

1 Answer
Jul 31, 2017

Answer:

#106.67# ml of water to be added.

Explanation:

Let #x# ml of water is added to dilute the acd solution.

Acid content in #35%# acid solution is # 80 * 0.35 = 28# ml

After adding , total quantity of #15%# acid solution is # 80 +x # ml

Acid content in #15%# acid solution is # (80+x) * 0.15 # ml

Quantity of acid remains same before and after dilution.

#:. (80+x) * 0.15 =28 or 80 +x = 28/0.15 = 186 2/3 #

#x = 186 2/3 - 80 = 106 2/3 ~~ 106.67# ml

#106.67# ml of water to be added [Ans]