# A charge of 12 C is passing through points A and B on a circuit. If the charge's electric potential changes from 60 J to 34 J, what is the voltage between points A and B?

Jun 1, 2018

The voltage is $= 2.17 V$

#### Explanation:

The charge is $Q = 12 C$

$Q = I t = 12 C$

The Energy is

$W = U I t$

Where the voltage is $= \left(U\right) V$

The change in energy is

$\Delta W = \Delta U \times I t$

Therefore,

$\Delta U = \frac{\Delta W}{I t} = \frac{60 - 34}{12} = 2.17 V$