# A charge of 5 C is passing through points A and B on a circuit. If the charge's electric potential changes from 22 J to 19 J, what is the voltage between points A and B?

Jul 13, 2018

The voltage is $= 0.6 V$

#### Explanation:

The charge is

$Q = I t = 5 C$

The Energy is

$W = U I t = U Q$

The change in the energy is

$\Delta W = Q \Delta U$

Therefore,

$\Delta U = \frac{\Delta W}{Q} = \frac{22 - 19}{5} = 0.6 V$