# A charge of 6 C is passing through points A and B on a circuit. If the charge's electric potential changes from 33 J to 9 J, what is the voltage between points A and B?

Feb 3, 2018

$4 V$

#### Explanation:

Relationship between voltage ($V$) and change in potential energy ($\delta U$) is given as,

$V = \frac{\delta U}{q}$ (i.e the energy change for bringing a charge $q$ in between two points )

Given, $\delta U = \left(33 - 9\right) J = 24 J$ and, $q = 6 C$

So, Volage is $\left(\frac{24}{6}\right) V = 4 V$