A charge of 8 C is passing through points A and B on a circuit. If the charge's electric potential changes from 64 J to 24 J, what is the voltage between points A and B?

Apr 13, 2018

The voltage is $= 5 V$

Explanation:

Apply the equation

$\text{Energy"(J)}$ $= \text{ Electric potential(V)"xx"Charge (C)}$

The charge is $Q = 8 C$

The change in energy is $\Delta E = 64 - 24 = 40 J$

The voltage is

${U}_{A B} = \frac{\Delta E}{Q} = \frac{40}{8} = 5 V$