# A chemist mixes a 200 L of a solution that is 60% acid with a 300 L of a solution that is 20% acid. What is the percentage of the mixture?

Aug 11, 2015

The resulting mixture is 36% acid.

#### Explanation:

The resulting mixture's acid proportion is

$\text{volume of acid in the solution"/"volume of the solution}$

The volume of the mixture is $200 + 300 = 500 L$

The volume of acid in the first solution is $0.6 \cdot 200 = 120 L$

The volume of acid in the second solution is $0.2 \cdot 300 = 60 L$

Therefore, the resulting mixture's acid proportion is:

(120+60)/500=180/500=36%