# A gas originally at a temperature of 23.13C. What temperature must it be heated to triple its volume with constant pressure? Answer in celsius units

May 11, 2018

Recall the relationship between those parameters,

$P V = n R T$

$\implies {V}_{1} / {T}_{1} = \frac{n R}{P} = {V}_{2} / {T}_{2}$

$\implies {V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

Generally,

$V \propto T$

So we expect an increase in temperature to accompany the increase in volume. If the volume increases by a factor of three, so must the temperature.

Hence,

3V_1 = 3T_1 = T_2 approx 69.39°"C"

is the temperature at which this gas (all else constant) will expand to three times its original volume.