# A huge meteor has a mass of 3.2*10^12 g. If the density of the meteor was 4.2 g/cm^3, what was the volume of the meteor?

Jan 6, 2016

$762000 {m}^{3}$

#### Explanation:

Since density is defined as the mass per unit volume, we may calculate the volume from this definition.

$\rho = \frac{m}{V} \implies V = \frac{m}{\rho}$.

$= \frac{3.2 \times {10}^{12} g}{4.2 g / c {m}^{3}}$

$= 7.62 \times {10}^{11} c {m}^{3}$

$= 762000 {m}^{3}$ in SI units.