A kite is flying at an angle of 42 degrees with the ground. All 70 meters of string have been let out. Ignoring the sag in the string, find the height of the kite to the nearest 10 meters?
1 Answer
Feb 13, 2016
The height is 70 sin(42 deg) = 46.84. Nearer 10 is 50 meters.
Explanation:
The string is the hypotenuse of a right angled triangle, with th inclination 42 deg to the horizontal side, Height is the vertical opposite side. sin(42) = (opposite side )/hypotenuse). So height is 70 sin(42).
