A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is #60 # and the height of the cylinder is #16 #. If the volume of the solid is #520 pi#, what is the area of the base of the cylinder?

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Answer 1 · 2016-06-01T13:57:12

Area of the base is #(130pi)/9#

Let the area of the base of cylinder be #A#.

Hence volume of cylinder is #Axx16=16A#

and volume of cone is #1/3xxAxx60=20A#

Hence total volume is #20A+16A=36A=520pi#

Therefore #A=(520pi)/36=(130pi)/9#