# A solid disk with a radius of 8 m and mass of 6 kg is rotating on a frictionless surface. If 960 W of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at 25 Hz?

$\text{6.1 Nm}$ of Torque is applied on disc.
$\text{Power = Torque × Angular Velocity}$
$\text{Torque" = "Power" / "Angular Velocity" = ("960 Watt") / ("2 π × 25 Hz") = "6.1 Nm}$