A triangle has sides A, B, and C. Sides A and B have lengths of 9 and 3, respectively. The angle between A and C is #(13pi)/24# and the angle between B and C is # (pi)/8#. What is the area of the triangle?

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Answer 1 · 2016-02-19T09:07:17

use the formula area = #1/2A.Bsintheta#

here the angle between sides Aand B = #theta #
So, #theta=pi-13pi/24-pi/8= pi-16pi/24=pi/3#
Hence area = #1/2*9*3*sin(pi/3)#= 6.75 squnit