# A vinegar-water solution is used to wash windows. If 1200L of a 28% solution are required, but only 16% and 36% solutions are available, how much of each should be mixed?

Mar 1, 2017

Volume of 16% solution is $= 480 L$
Volume of 36% solution is $= 720 L$

#### Explanation:

Let $V =$ volume of 16% solution

Then,

$\left(1200 - V\right)$ is the volume of the 36% solution

Therefore,

We perform a material balance wrt vinegar

$1200 \cdot 0.28 = V \cdot 0.16 + \left(1200 - V\right) \cdot 0.36$

$336 = 0.16 V + 432 - 0.36 V$

$0.36 V - 0.16 V = 432 - 336$

$0.20 V = 96$

$V = \frac{96}{0.20} = 480 L$

And,

$1200 - 480 = 720 L$