According to the following reaction, how many grams of hydrogen peroxide (#H_2O_2#) are necessary to form 0.182 moles oxygen gas?

hydrogen peroxide (#H_2O_2#) (aq) #-># water (l) + oxygen (g)

1 Answer
Mar 4, 2017

Answer:

12.736 grams of hydrogen peroxide. please read explanation.

Explanation:

#2H_"2"O_"2"# #rarr# #2H_"2"O# + #O_"2"#

As per the mole ratio, 2 moles of hydrogen peroxide burns to form 1 mole of oxygen. The ratio is 2:1.
steps :

multiply 0.182 with 2 to find out total moles of hydrogen peroxide
answer = 0.364

to convert from moles to grams multiply the moles with molar mass
molar mass of hydrogen peroxide = 34

0.364*34 = 12.376 grams of hydrogen peroxide