An object with a mass of # 3 kg# is traveling in a circular path of a radius of #15 m#. If the object's angular velocity changes from # 5 Hz# to # 3Hz# in # 5 s#, what torque was applied to the object?

1 Answer
Feb 10, 2016

Answer:

#L=-540pi#

Explanation:

#alpha=L/I#
#alpha": angular acceleration"#
#"L:torque"#
#"I:moment of inertia"#
#alpha=(omega_2-omega_1)/ (Delta t)#
#alpha=(2 pi*3-2 pi*5)/5#
#alpha=-(4pi)/5#
#I=m*r^2#
#I=3*15^2#
#I=3*225=675#
#L=alpha*I#
#L=-4pi/5*675#
#L=-540pi#