An object with a mass of # 6 kg# is traveling in a circular path of a radius of # 1m#. If the object's angular velocity changes from # 6 Hz# to # 7 Hz# in #3 s#, what torque was applied to the object?

1 Answer

Answer:

#\tau = 12.562 N\cdotm#

Explanation:

First, convert the given angular velocities to #(rad)/s# where #1Hz = (2\pi)(rad)/s #
Therefore,
#6Hz = 37.699 (rad)/(s)#
#7Hz = 43.98 (rad)/(s)#

Torque is
#\tau=Fl = mal#

Finding for the tangential acceleration, use
#v=v_0+at#
where #a = 2.09367 m/s^2#

Therefore,
#\tau = (6 kg)\cdot(2.09367 m/s^2)\cdot(1 m)#
#\tau = 12.562 N\cdotm#