An object with a mass of # 8 kg# is traveling in a circular path of a radius of #12 m#. If the object's angular velocity changes from # 5 Hz# to # 4 Hz# in # 5 s#, what torque was applied to the object?

1 Answer
Feb 22, 2016

Answer:

#L=230,4 N*m#

Explanation:

#L=alpha*I#
#L:" Torque"#
#alpha:" angular acceleration"#
#I:" moment of inertia of object"#
#alpha=(Delta w)/(Delta t)#
#alpha=(2*pi(4-5))/5#
#alpha=-(2*pi)/5#
#I=m*r^2#
#I=8*12^2=144*8=1152#
#L=-(1152*2*pi)/5#
#L=230,4 N*m#