# Each pair of points (5.4 , 3) and (2, y) is on the graph of an inverse variation, how do you find the missing value?

##### 1 Answer

Nov 27, 2017

#### Answer:

#### Explanation:

#"the initial statement is "yprop1/x#

#"to convert to an equation multiply by k the constant"#

#"of variation"#

#rArry=kxx1/x=k/x#

#"to find k use "(5.4,3)" that is x = 5.4 and y = 3"#

#y=k/xrArrk=yx=3xx5.4=16.2#

#"the equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(y=16.2/x)color(white)(2/2)|)))#

#"when "x=2#

#y=16.2/2=8.1#

#rArr(2,y)=(2,8.1)#