Find the maximum amount of ozone(O3) by removing all of its oxygen atomes?

1 Answer
Aug 29, 2017

Answer:

There are #(196*g)/(98.08*g*mol^-1)=2.0*mol# #"sulfuric acid"#.

Explanation:

And thus we gots #2.0*molxx4=8*mol# oxygen ATOMS........which represents a mass of #8.0*molxx16.00*g*mol^-1=128*g# WITH RESPECT TO OXYGEN.....

And since #O_3# has a mass of #48.0*g*mol^-1#....we could conceivably make #(128.0*g)/(48.0*g*mol^-1)=2.67*mol#.

Please note that I cannot conceive of a process that would efficiently oxidize up the oxygen atoms in sulfuric acid to give ozone.....