# Find the maximum amount of ozone(O3) by removing all of its oxygen atomes?

Aug 29, 2017

There are $\frac{196 \cdot g}{98.08 \cdot g \cdot m o {l}^{-} 1} = 2.0 \cdot m o l$ $\text{sulfuric acid}$.
And thus we gots $2.0 \cdot m o l \times 4 = 8 \cdot m o l$ oxygen ATOMS........which represents a mass of $8.0 \cdot m o l \times 16.00 \cdot g \cdot m o {l}^{-} 1 = 128 \cdot g$ WITH RESPECT TO OXYGEN.....
And since ${O}_{3}$ has a mass of $48.0 \cdot g \cdot m o {l}^{-} 1$....we could conceivably make $\frac{128.0 \cdot g}{48.0 \cdot g \cdot m o {l}^{-} 1} = 2.67 \cdot m o l$.