Question

For `f(t)= (1/(t-3),t^2)` what is the distance between `f(0)` and `f(2)`?

Answer 1

`D = (2 sqrt {37})/3`

Explanation:

`f(0) = (1/-3, 0)`

`f(2) = (1/(2-3), 4)`

`D^2 = (-1/3 - (-1))^2 + (0 - 4)^2 = 4/9 + 16`

`D = sqrt {148/9}`