Question

For `f(t)= (sin2t,cos^2t)` what is the distance between `f(pi/4)` and `f(pi)`?

Answer 1

`=sqrt5/2unit`

Explanation:

putting `t=pi/4`
`f(pi/4)=(sin(2pi/4),cos^2(pi/4))=(1,1/2)`
putting `t=pi`
`f(pi)=(sin(2pi),cos^2(pi))=(0,1))`
So the distance `=sqrt((1-0)^2+(1/2-1)^2)=sqrt5/2unit`