Question

For `f(t)= ( t-2, sqrtt -t )` what is the distance between `f(0)` and `f(1)`?

Answer 1

1

Explanation:

`f(t)=(t-1,sqrt(t)-6)`
`t=0 => f(0)=(0-2, sqrt(0)-0) = (-2,0)`
`t=1 => f(1)=(1-2, sqrt(1)-1) = (-1,0)`

These two points lie in a straight line do distance between the points = 1