For #f(t)= (t-2,-t^2-2t)# what is the distance between #f(2)# and #f(5)#?

Question

1309 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-10T20:18:30

The distance is #=27.17#

We start by calculating #f(2)# and #f(5)#

#f(t)=(t-2, -t^2-2t)#

#f(2)=(0,-8)#

#f(5)=(3,-35)#

The distance between #(0,-8)# and #(3,-35)# is

#=sqrt((3-0)^2+(-35+8)^2)#

#=sqrt(9+729)#

#=sqrt738#

#=27.17#