Question

Given a right triangle with a height of 5 a hypotenuse of 14, how do you find the angle measure of the two missing angle measures?

Answer 1

Missing angles are `20.92^0(2dp) and 69.08^0(2dp)`

Explanation:

Let ABC be the triangle , `AB=5 ; AC=14 ; /_B=90^0` We know by sine law ; `(AB)/sinC=(AC)/sinB or 5/sinC=14/sin90 or sin C = (5*1)/14 or /_C= sin^-1(5/14)= 20.92^0(2dp) :. /_A= 180-(90+20.92) =69.08^0(2dp)`[Ans]