Given the vectors #u=<2,2>#, #v=<-3,4>#, and #w=<1,-2>#, how do you find #2-||u||#? Precalculus Dot Product of Vectors The Dot Product 1 Answer Tazwar Sikder Sep 22, 2016 #2 - 2 sqrt(2)# Explanation: We have: #u = <2, 2># #=> 2 - abs(u) = 2 - abs(<2, 2>)# #=> 2 - abs(u) = 2 - sqrt(2^(2) + 2^(2))# #=> 2 - abs(u) = 2 - sqrt(4 + 4)# #=> 2 - abs(u) = 2 - sqrt(8)# #=> 2 - abs(u) = 2 - 2 sqrt(2)# Answer link Related questions What is the dot product of two vectors? What is the cross product of two vectors? How do I find a vector cross product on a TI-84? How do I find a vector cross product on a TI-89? How do I find the cross product of #<-13, 4># and #<-56, 0>#? How do I find the dot product of #<2, 3># and #<4, −7>#? How do I find the dot product of vectors #v =2i-3j# and #w= i-j#? How do I find the dot product of vectors #v =5i-2j# and #w=3i+4j#? How can vector dot products be used to prove the law of cosines? Consider the following vectors: v = 3i + 4j, w = 4i + 3j, how do you find the dot product v·w? See all questions in The Dot Product Impact of this question 1515 views around the world You can reuse this answer Creative Commons License