Question

Given x(t)=3sin(t) - 3, y(t)=t-1 for 0 is less than or equal to t is less than or equal to 2pi How do you find the position of the particle at t=3?

Answer 1

`(-2.6, 2.0)`

Explanation:

We have x and y parameterised in terms of t. We simply sub `t=3` into these expressions for x and y to obtain the position:

`x(3) = 3sin(3) - 3 = -2.577`

`y(3) = 3-1 = 2`

Position is `(-2.6, 2.0)`