# Given x(t)=3sin(t) - 3, y(t)=t-1 for 0 is less than or equal to t is less than or equal to 2pi How do you find the velocity of the particle at t=3?

##### 1 Answer

Jun 23, 2018

#### Answer:

The particle's velocity is

#### Explanation:

We can find the

#{(x'(t)=3cos(t)),(y'(t)=1):}#

So at

#{(x'(3)=3cos(3)),(y'(3)=1):}#

The magnitude of the velocity is then the hypotenuse of the right triangle whose legs are the

#v(3)=sqrt((x'(3))^2+(y'(3))^2)=sqrt(9cos^2(3)+1)approx3.1338#