How can you use trigonometric functions to simplify  17 e^( ( 13 pi)/12 i )  into a non-exponential complex number?

Apr 5, 2016

$17 \cos \left(\frac{13 \pi i}{12}\right) + 17 i \sin \left(\frac{13 \pi i}{12}\right)$

or $- 16.420739046913 - 4.399923766751 i$

Explanation:

$17 {e}^{\frac{13 \pi i}{12}}$ is equivalent to$17 \cos \left(\frac{13 \pi i}{12}\right) + 17 i \sin \left(\frac{13 \pi i}{12}\right)$
which gives

-16.420739046913- 4.399923766751.i