# How can you use trigonometric functions to simplify  26 e^( ( pi)/2 i )  into a non-exponential complex number?

$26 i$
$\textcolor{b l u e}{\rho {e}^{\theta i} = \rho \cos \left(\theta\right) + \rho i \sin \left(\theta\right)}$
$26 {e}^{\left(\frac{\pi}{2}\right) i} = 26 \cos \left(\frac{\pi}{2}\right) + 26 i \sin \left(\frac{\pi}{2}\right)$
$= 26 \cdot 0 + 26 i \cdot 1 = 26 i$