How do I find the cube of #(2 x + 5)#? Precalculus The Binomial Theorem Powers of the Binomial 1 Answer Hope It Helps Apr 1, 2018 #8x^3+65x^2+150x+125# Explanation: #(2x+5)# cubed = #(2x+5)^3# #(2x+5)^3 = (2x+5)(2x+5)(2x+5)# First, do #(2x+5)(2x+5)=4x^2+20x+25# Now do the second part: #(4x^2+20x+25)(2x+5)# #8x^3+65x^2+150x+125# Answer link Related questions What is meant by a power of a binomial? How do I find the cube of #(2b + 6x)#? How do I find the cube of #(4 x - 5b)#? How do I find #(3+i)^4#? What happens when you square a binomial? How do I find the square of a binomial? What is the formula for squaring a binomial? What is the formula for #(a+b)^3#? What is #(x+y)^2#? What is meant by cubing a binomial? See all questions in Powers of the Binomial Impact of this question 5915 views around the world You can reuse this answer Creative Commons License